How do you graph $y = sin(pi/2x + (3pi)/2)$ ?

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Answer 1 · 2018-01-08T15:38:54

I'm assuming you want

$y = sin(pi/2x + (3pi)/2)$

In standard form. Use the sum formula for sine, which is $sin(A + B) = sinAcosB + cosAsinB$ .

$y = sin(pi/2x)cos((3pi/2)) + cos(pi/2x)sin((3pi)/2)$

As long as you know you trigonometric function values at $pi/2$ and $(3pi)/2$ , you're good to go.

$y = sin(pi/2x)(0) - 1(cos(pi/2x))$

$y = -cos(pi/2x)$

If you graph $f(x) = sin(pi/2x + (3pi)/2)$ and $g(x) = -cos(pi/2x)$ , you'll see they're indeed the same graphs.

enter image source here

Hopefully this helps!

How do you graph y = sin(pi/2x + (3pi)/2)y = sin(pi/2x + (3pi)/2)?