What is the simplest radical form of $sqrt64$ ?

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Answer 1 · 2017-02-20T09:27:15

$sqrt64 = sqrt(2^6) =+-8$

The "simplest radical form" of $sqrt 64$ is $sqrt (2^6)$ if we define "simplest form" as a radical of a prime to an integer power.

However. since $sqrt (2^6) = +-2^3$

The simplest answer to this question is $+-8$

What is the simplest radical form of sqrt64sqrt64?