How many moles of sodium chloride are present in $58 \cdot g$ $58*g$ of the salt?

Question

9712 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-15T21:55:06

The molar mass of sodium chloride is in fact $58.44 \cdot g$ $58.44*g$ .....

Molar mass of NaCl

$=$ $=$ $Atomic mass of sodium + atomic mass of chlorine$ $"Atomic mass of sodium + atomic mass of chlorine"$

$=$ $=$ $(22.99 + 35.45) \cdot g \cdot m o l^{- 1} .$ $(22.99+35.45)*g*mol^-1.$

From where do you get these atomic masses?

The number of moles of sodium chloride in a mass of $58 \cdot g$ $58*g$ sodium chloride is given by the quotient,

$"Mass"/"Molar mass"=(58*cancelg)/((22.99+35.45)*cancelg*mol^-1)$ $=$

$"A tad under one mole."$

Note that this is dimensionally consistent in that $1/(mol^-1)=1/(1/(mol))=mol$ as required.