What is the mass associated with $4.70 \times 10^{22}$ $4.70xx10^22$ $sulfur atoms$ $"sulfur atoms"$ ?

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What is the mass associated with $4.70 \times 10^{22}$ $4.70xx10^22$ $sulfur atoms$ $"sulfur atoms"$ ?

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Answer 1 · 2017-02-15T21:12:59

$Approx. 2.5 g$ $"Approx. 2.5 g"$

Explanation:

We know that $N_{A}, Avogadro's number,$ $N_A,"Avogadro's number,"$ $6.022 \times 10^{23}$ $6.022xx10^23$ of $sulfur atoms$ $"sulfur atoms"$ have a mass of $32.06 \cdot g$ $32.06*g$ precisely. How do we know this?

And thus we can multiply the number quotient by the molar mass to give:

$\frac{4.70 \times 10^{22} \cdot sulfur atoms}{6.022 \times 10^{23} \cdot m o l^{- 1} \cdot sulfur atoms} \times 32.06 \cdot g \cdot m o l^{- 1} \equiv$ $(4.70xx10^22*"sulfur atoms")/(6.022xx10^23*mol^-1*"sulfur atoms")xx32.06*g*mol^-1-=$

$? ? g$ $??g$

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What is the mass associated with $4.70 \times 10^{22}$ $4.70xx10^22$ $sulfur atoms$ $"sulfur atoms"$ ?

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What is the mass associated with 4.70×10224.70xx10^22 sulfur atoms"sulfur atoms"?

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What is the mass associated with $4.70 \times 10^{22}$ $4.70xx10^22$ $sulfur atoms$ $"sulfur atoms"$ ?