How many atoms are in "0.390 g P"_2"O"0.390 g P2O?

1 Answer
Feb 27, 2017

"0.390 g P"_2"O"0.390 g P2O contains 9.04xx10^21 color(white)(.)"atoms"9.04×1021.atoms.

Explanation:

The process for determining the number atoms in "0.390 g P"_2"O"0.390 g P2O involves the following steps:

"molar mass"molar massrarr"moles of molecules"moles of moleculesrarr"number of molecules"number of moleculesrarr"number of atoms"number of atoms

Determine molar mass of "P"_2"O"P2O.

Determine the molar mass of "P"_2"O"P2O. I looked it up online and found it to be "77.947 g/mol"77.947 g/mol (rounded to five significant figures).
http://www.webqc.org/molecular-weight-of-P2O.html

Determine moles of molecules "P"_2"O"P2O
In order to determine moles of "P"_2"O"P2O, we divide the given mass in the question by the molar mass.

(0.390color(red)cancel(color(black)("g")))/(77.947color(red)cancel(color(black)("g"))/"mol")="0.0050034 mol P"_2"O"

I am leaving some extra digits in the number of moles to reduce rounding errors. I will round the final answer to three significant figures.

Determine number of molecules.

Multiply the moles of "P"_2"O" by 6.022xx10^23 molecules.

0.0050034color(red)(cancel(color(black)("mol")))xx(6.022xx10^23"molecules")/color(red)(cancel(color(black)("mol")))=3.0130xx10^21"molecules"

Determine number of atoms of "P"_2"O".

Since every molecule of "P"_2"O" consists of three atoms, multiply 3.0130xx20^21"molecules" by "3 atoms/molecule".

3.0130xx10^21 color(red)cancel(color(black)("molecules"))xx(3color(white)(.)"atoms")/color(red)(cancel(color(black)("molecule")))=9.04 xx10^21color(white)(.)"atoms" (rounded to three significant figures)