Question #221ff

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Question #221ff

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Answer 1 · 2017-02-23T17:31:46

$\sqrt{72 a^{19}} = 6 ∣ ∣ a^{9} ∣ ∣ \sqrt{2 a}$ $sqrt(72a^19)=6abs(a^9)sqrt(2a)$

Explanation:

To find the square root of the given algebraic expression we
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should find the prime factorization.
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$72 = 2 \times 36$ $72=2xx36$
$72 = 2 \times 2 \times 18$ $72=2xx2xx18$
$72 = 2 \times 2 \times 2 \times 9$ $72=2xx2xx2xx9$
$72 = 2 \times 2 \times 2 \times 3 \times 3$ $72=2xx2xx2xx3xx3$
$72 = 2^{3} \times 3^{2}$ $72=2^3xx3^2$
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$72 a^{19} = 2^{3} \times 3^{2} \times {(a^{9})}^{2} \times a$ $72a^19=2^3xx3^2xx(a^9)^2xxa$
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$\sqrt{72 a^{19}} = \sqrt{2^{3} \times 3^{2} \times {(a^{9})}^{2} \times a}$ $sqrt(72a^19)=sqrt(2^3xx3^2xx(a^9)^2xxa)$
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$\sqrt{72 a^{19}} = \sqrt{2^{2} \times 2 \times 3^{2} \times {(a^{9})}^{2} \times a}$ $sqrt(72a^19)=sqrt(2^2xx2xx3^2xx(a^9)^2xxa)$
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$\sqrt{72 a^{19}} = \sqrt{{(2 \times 3 \times a^{9})}^{2} \times 2 \times a}$ $sqrt(72a^19)=sqrt((2xx3xxa^9)^2xx2xxa)$
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$\sqrt{72 a^{19}} = ∣ ∣ 2 \times 3 \times a^{9} ∣ ∣ \sqrt{2 \times a}$ $sqrt(72a^19)=abs(2xx3xxa^9)sqrt(2xxa)$
$" "$
$\sqrt{72 a^{19}} = 6 ∣ ∣ a^{9} ∣ ∣ \sqrt{2 a}$ $sqrt(72a^19)=6abs(a^9)sqrt(2a)$

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Question #221ff

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