What mass of caustic soda are required to prepare a solution of $100mL$ volume that is $1.0mol*L^-1$ with respect to $NaOH$ ?

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Answer 1 · 2017-02-27T08:42:10

A mass of $4.0*g$ $"sodium hydroxide"$ is required............

$"Concentration"$ $=$ $"Moles of solute"/"Volume of solution"$

Here, $"concentration"$ $=$ $1.0*mol*L^-1$ , $"volume"$ $=$ $100*mL$ .

And thus $"moles of solute"$ $=$ $"Concentration "xx" Volume"$

$=1*mol*L^-1xx100xx10^-3L=0.100*mol$ .

And thus $"mass of solute"$ $=$ $"number of moles "xx" molar mass"$

$=0.100*molxx40.0*g*mol^-1=??*g$ .

What mass of caustic soda are required to prepare a solution of 100*mL100*mL volume that is 1.0*mol*L^-11.0*mol*L^-1 with respect to NaOHNaOH?