Question

Find the equation of the straight that passes through the points `(0, 1)` and `(2, 4)` ?

Answer 1

`y=3/2x+1`

Explanation:

To find the slope `(m)` of the straight line that passes through two points `(x_1, y_1)` and `(x_2, y_2)` apply:

`(y_1 - y_2) = m(x_1 -x_2)`

In this example our two points are `(0, 1)` and `(2, 4)`

Hence: `(1-4) = m(0-2)`

`-3 = -2m -> m=3/2`

The equation of a straight line in slope `(m)` and intercept `(c)` form is:

`y=mx+c`

In this example:

`y=3/2x + c`

Since the point `(0, 1)` is on this line `-> 1=0+c`

Hence, `c=1`

`:. y = 3/2x+1` is our required straight line.