Question #9cc39

Question

1867 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-18T00:16:44

$x^2+y^2 = 6/4x+7y$

You will need to know these subsitutions:

$r^2=x^2+y^2$
$cos(theta) = x/r$
$sin(theta) = y/r$

Follow along these steps:

$r = 6/4costheta+7sintheta$

Substitute $costheta$ and $sintheta$ with their appropriate substitutions.

$r = 6/4*x/r+7*y/r$

Multiply both sides by $r$

$r^2 = 6/4x+7y$

Substitute $r^2$ with it's appropriate substitution

$x^2+y^2 = 6/4x+7y$

This is a valid rectangular equation.