Question #518c1

1 Answer
Feb 28, 2017

Allyson is 7 years old now.

Explanation:

The key to this problem is the fact that the difference between their ages remains constant as they get older.

So, you know that at the moment, Jenny is y^2 years old and Allyson is y years old. The difference between their ages, let's say Delta_"age", can be written as

Delta_"age" = y^2 - y

Let's say that exactly 1 year passes. Jenny's age will now be

"Jenny: " y^2 + 1

and Allyson's age will now be

"Allyson: " y + 1

But the difference between their ages remains the same, since

Delta_"age" = y^2 + 1 - (y + 1)

Delta_"age" = y^2 + color(red)(cancel(color(black)(1))) - y - color(red)(cancel(color(black)(1)))

Delta_"age" = y^2 - y

This means that regardless of how many years pass, the difference between the ages of the two girls will always be equal to y^2 - y.

Now, we know that when Jenny is 13y years old, Allyson will be y^2 years old. The difference between their ages will be

Delta_"age now" = 13y - y^2

But this must be equal to

Delta_"age"= y^2 - y

You can thus say that

y^2 - y = 13y - y^2

This is equivalent to

2y^2 - 14y = 0

which simplifies to

2y(y - 7) = 0

You now have two possibilities here

2y = 0" " or " "y-7=0

Notice that

2y = 0 implies y = 0

is not really a suitable solution here because Jenny and her daughter cannot be 0 years old.

This means that the only suitable solution will be

y - 7 = 0 implies color(darkgreen)(ul(color(black)(y = 7)))

Therefore, you can say that at the moment, Allyson is 7 years old and her mother is

7^2 = 49

years old. Notice that when Jenny is

13 * 7 = 91

years old, her daughter will be

91 - overbrace((49 - 7))^(color(blue)("the difference between their ages")) = 49

years old, which is equal to 7^2.