Question #5789c

Question

Question #5789c

2 Answers

Impact of this question

1345 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-09T19:40:05

$\frac{23}{25}$ $23/25$

Explanation:

enter image source here

Answer 2 · 2017-03-10T05:53:03

$11^{\circ} 54 + k 180^{\circ}$ $11^@54 + k180^@$

Explanation:

$cos (2 arcsin (\frac{1}{5})$ $cos (2arcsin (1/5)$ --> cos 2x with $sin x = \frac{1}{5}$ $sin x = 1/5$
Use trig identity:
$cos 2 x = 1 - 2 {sin}^{2} x$ $cos 2x = 1 - 2sin^2 x$
$cos 2 x = 1 - \frac{2}{25} = \frac{23}{25}$ $cos 2x = 1 - 2/25 = 23/25$
Use calculator and unit circle -->
$cos 2 x = \frac{23}{25}$ $cos 2x = 23/25$ --> $2 x = \pm 23^{\circ} 07 + k 360^{\circ}$ $2x = +- 23^@07 + k360^@$ -->

$x = \pm 11^{\circ} 54 + k 180^{\circ}$ $x = +- 11^@54 + k180^@$

Science

Math

Humanities

... and beyond

Question #5789c

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question