Simplify 5lnx +21lnx^3-3lnx^3+lnx^(1/2)? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Mar 3, 2017 5lnx +21lnx^3-3lnx^3+lnx^(1/2)=119/2lnx Explanation: We can use the identities lna+lnb-lnc=ln((ab)/c) and lna^b=blna. Hence, 5lnx +21lnx^3-3lnx^3+lnx^(1/2) = 5lnx +21xx3lnx-3xx3lnx+1/2lnx = 5lnx +63lnx-9lnx+1/2lnx = lnx(5+63-9+1/2) = lnx(59+1/2) = 119/2lnx Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1878 views around the world You can reuse this answer Creative Commons License