Question

Question #6489d

Answer 1

The question does not state if you require the amount reduced by or the final figure left after the reduction.

`65%" of "80=52`

`80-52=28`

Explanation:

`color(blue)("Preamble")`

There are two things to remember hear.

1: We are talking about a change that is a reduction. So the answer `" "`is a negative value.

2: The symbol % is a bit like units of measurement and that is worth `" "1/100` So 65%`->65xx1/100 = 65/100`

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`color(blue)("Answering the question")`

This is a reduction so the amount it is reduced by is: `65/100xx80`

There are several paths that can be followed now but they all lead to the same point.

With practice you could some of this in your mind.

Write as `65xx80/100 " "->" "65xx(80-:10)/(100-:10) = 65xx8/10`

`=65/100xx8" "=" "6.5xx8`

`6xx8=" "48`
`1/2xx8=" "ul(color(white)(.)4)larr" add"`
`" "52`

But this a reduction so the answer to this part is: `-52`
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