Question #9c80e

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Question #9c80e

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Answer 1 · 2017-05-01T03:49:37

$\frac{\sqrt{3}}{2}$ $sqrt(3)/2$

Explanation:

For a $30^{\circ} - 60^{\circ} - 90^{\circ}$ $30^@-60^@-90^@$ triangle, the angles are in the ratio: $1 : \sqrt{3} : 2$ $1: sqrt(3): 2$ .

$120^{\circ}$ $120^@$ is in the second quadrant. Sine is positive in this quadrant. Using $s o h, sin θ = \frac{opposite}{hypotenuse} = \frac{\sqrt{3}}{2}$ $soh, sin theta = "opposite"/"hypotenuse" = sqrt(3)/2$ .

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