Question #d208e

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Question #d208e

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Answer 1 · 2017-03-08T06:23:44

$(- 3, \frac{11}{4})$ $(-3, 11/4)$

Explanation:

The equation of L1,
$\frac{(y - (- 1))}{(x - (- 8))} = \frac{((- 1) - 2)}{((- 8) - (- 4))}$ $((y - (-1)))/((x - (-8))) = (((-1) - 2))/(((-8) - (-4)))$

$\frac{y + 1}{x + 8} = \frac{- 3}{- 4}$ $(y + 1)/(x +8) = (-3)/(-4)$

$(y + 1) = (\frac{3}{4}) (x + 8)$ $(y + 1) = (3/4)(x + 8)$

$4 (y + 1) = 3 (x + 8)$ $4(y + 1) = 3(x + 8)$

$4 y + 4 = 3 x + 24$ $4 y + 4 = 3 x +24$

$4 y = 3 x + 20$ $4 y = 3 x +20$

L1,===> $4 y = 3 x + 20$ $4 y = 3 x +20$

L2,===> $4 y = 8 - x$ $4 y = 8 - x$

L1 - L2,
$0 = 4 x + 12$ $0 =4 x +12$
$4 x = - 12$ $4 x = -12$ , $x = - 3$ $x =-3$

Replace $x = - 3$ $x = -3$ into L1 or L2

$4 y = 8 - (- 3)$ $4 y = 8 - (-3)$
$4 y = 11$ $4 y = 11$ , $y = \frac{11}{4}$ $y = 11/4$

Therefore the intersection of L1 & L2 is $(- 3, \frac{11}{4})$ $(-3, 11/4)$

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Question #d208e

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