Question #bef4d

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Question #bef4d

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Answer 1 · 2017-03-05T08:42:00

$w = - 1 \pm \sqrt{\frac{5}{6}}$ $w = -1pmsqrt(5/6)$

Explanation:

Making $z = x^{2}$ $z=x^2$ we get

$6 z^{2} + 7 z - 10 = 0$ $6z^2+7z-10=0$ Solving for $z$ $z$

$z = {- 2, \frac{5}{6}}$ $z = {-2,5/6}$ . Following with $z = x^{2} = \frac{5}{6}$ $z=x^2=5/6$ contemplating only real solutions for $x$ $x$ , we have now

$x^{2} = {(w + 1)}^{2} = \frac{5}{6}$ $x^2=(w+1)^2=5/6$ then

$w + 1 = \pm \sqrt{\frac{5}{6}}$ $w+1 = pm sqrt(5/6)$ and finally

$w = - 1 \pm \sqrt{\frac{5}{6}}$ $w = -1pmsqrt(5/6)$

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