Question #622f7

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Answer 1 · 2017-03-13T04:46:52

Mass of solvent( $CH_4O_2$ )=300 g

Mass of solute ( $HNO_3$ )=7.5 g

Mass of solution (w)=307.5g

Density of solution (d) = $0.95" g/"mL$

Volume of solution (V) = $w/d=(307.5g)/(0.95" g/"mL)$
$~~323.7mL=0.3237L$

Number of moles of $HNO_3$ in 7.5g is $=(7.5g)/(63" g/"mol)$

$~~0.12mol$

So strength of $HNO_3$

$=0.12/0.3237M~~0.37M$