The chemical equation is
#"H"_2"SO"_4 + "2LiOH" → "Li"_2"SO"_4 + "2H"_2"O"#
Step 1. Calculate the moles of #"LiOH"#
#"Moles of LiOH" = 0.225 color(red)(cancel(color(black)("L LiOH"))) × "0.150 mol LiOH"/(1 color(red)(cancel(color(black)("L LiOH")))) = "0.033 75 mol LiOH"#
Step 2. Calculate the moles of #"H"_2"SO"_4#
#"Moles of H"_2"SO"_4 = "0.033 75" color(red)(cancel(color(black)("mol LiOH"))) × ("1 mol H"_2"SO"_4)/(2 color(red)(cancel(color(black)("mol LiOH")))) = "0.016 88 mol H"_2"SO"_4#
Step 3. Calculate the volume of #"H"_2"SO"_4#
#"Volume of H"_2"SO"_4 = "0.016 88" color(red)(cancel(color(black)("mol H"_2"SO"_4))) × ("1 L H"_2"SO"_4)/(0.25 color(red)(cancel(color(black)("mol H"_2"SO"_4)))) = "0.068 L H"_2"SO"_4 = "68 mL H"_2"SO"_4#
