If $BE$ || $CD$ , find $x$ ?

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Answer 1 · 2017-03-13T11:59:04

$x=10$

As $BE$ || $CD$ , $DeltaABE$ and $DeltaACD$ are similar.

Hence, $(AB)/(BC)=(AE)/(ED)$

i.e. $25/15=(7x-40)/(18)$

or $15xx(7x-40)=25xx18$

or $105x-600=450$

i.e. $105x=450+600=1050$

and $x=1050/105=10$

Answer 2 · 2017-03-13T12:06:18

$x=10.$

Lines $BE, and CD$ are Parallel, and, $AC and AD$ are

transverses. Therefore, by Geometry, we know that,

$(AB)/(BC)=(AE)/(ED) rArr 25/15=(7x-40)/18.$

$rArr 7x-40=25/15*18=30 rArr 7x=30+40.$

$:. x=70/7=10.$

Enjoy Maths.!

If BEBE||CDCD, find xx?