How do you simplify $(m^{4} n^{- 2}) (m^{2} n^{3})$ $(m^4n^-2)(m^2n^3)$ ?

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How do you simplify $(m^{4} n^{- 2}) (m^{2} n^{3})$ $(m^4n^-2)(m^2n^3)$ ?

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Answer 1 · 2017-03-14T00:11:34

See the entire solution process below:

Explanation:

First, rewrite this expression as:

$(m^{4} \cdot m^{2}) (n^{- 2} \cdot n^{3})$ $(m^4 * m^2)(n^-2 * n^3)$

Next, use this rule of exponents to combine the terms:

$x^{a} \times x^{b} = x^{a + b}$ $x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))$

$(m^{4} \cdot m^{2}) (n^{- 2} \cdot n^{3}) = m^{4 + 2} x^{- 2 + 3} = m^{6} n^{1}$ $(m^color(red)(4) * m^color(blue)(2))(n^color(red)(-2) * n^color(blue)(3)) = m^(color(red)(4) + color(blue)(2))x^(color(red)(-2) + color(blue)(3)) = m^6n^1$

Now, use this rule of exponents to complete the simplification:

$a^{1} = a$ $a^color(red)(1) = a$

$m^{6} n^{1} = m^{6} n$ $m^6n^color(red)(1) = m^6n$

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How do you simplify $(m^{4} n^{- 2}) (m^{2} n^{3})$ $(m^4n^-2)(m^2n^3)$ ?

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