Question #09020

1 Answer
Anthony R. ยท Stefan V.
Mar 14, 2017

= 3.32 mol Au

Explanation:

Use:

20.0*10^23 cancel("Au atoms") *(1 mol)/(6.022xx10^23 cancel("Au atoms"))

= 3.32 mol Au since there are 3 significant figures!

I hope this helps!

Related questions
See all questions in The Mole
Impact of this question
1529 views around the world
You can reuse this answer
Creative Commons License