Question #47d0a

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Question #47d0a

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Answer 1 · 2017-03-15T18:31:27

See below.

Explanation:

If $A$ $A$ and $B$ $B$ are non null hermitian then $tr (A^{2}) > 0$ $"tr"(A^2) > 0$ and $tr (B^{2}) > 0$ $"tr"(B^2) > 0$ so $tr (A^{2}) + tr (B^{2}) > 0$ $"tr"(A^2) +"tr"(B^2) >0$

so if $A^{2} + B^{2} = 0 \to A = 0, B = 0$ $A^2+B^2=0->A=0,B=0$

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