Question #885c3

1 Answer
Jan 5, 2018

This problem demands a fairly deep understanding of thermodynamic relationships.

The universe in this problem is but the system and the surroundings.

CaO(s) + H_2O(l) rightleftharpoons Ca(OH)_2(s)

Consider,

DeltaS_("univ") = DeltaS_("sys") + DeltaS_("surr"),

The change in enthalpy or entropy of a system is the sum of the property for products less the sum of the property for reactants,

DeltaS = (DeltaH)/T, and,

-DeltaH_("sys") = DeltaH_("surr")
=> -(DeltaH_("sys"))/T = (DeltaH_("surr"))/T
=> DeltaS_("surr") = -(DeltaH_("sys"))/T

Hence,

DeltaH_("sys") = -65.2kJ
therefore DeltaH_("surr") = 65.2kJ, and DeltaS_"surr" = (6.52*10^4J)/(298K) approx (218.7J)/K

Moreover,

DeltaS_"sys" = (-26.4J)/K

DeltaS_("univ") = DeltaS_"surr" + DeltaS_"sys" approx (192.3J)/K

I'm open to feedback if I made a mistake!