Question #5e54d

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Answer 1 · 2017-03-17T14:08:12

$= a^{6} b + 2 a^{5} b + a^{5} b^{2} + 3 a^{4} b^{2} + a^{3} b^{3}$ $=a^6b +2a^5b+a^5b^2+3a^4b^2+a^3b^3$

$(a \cdot a (a + b) \cdot a b (a^{2} + b + a + a)$ $(color(red)(a*a)(a+b)*color(red)(ab)(a^2+b+color(blue)(a+a))$

$= a^{3} b (a + b) (a^{2} + b + 2 a)$ $=color(red)(a^3b)(a+b)(a^2+b+color(blue)(2a))$

$= a^{3} b (a + b) (a^{2} + 2 a + b) \leftarrow$ $=a^3b(color(magenta)(a)color(forestgreen)(+b))(a^2+2a+b)" "larr$ multiply the two brackets

$= a^{3} b (a^{3} + 2 a^{2} + a b + a^{2} b + 2 a b + b^{2})$ $=a^3b(color(magenta)(a^3+2a^2+ab)+color(forestgreen)(a^2b+2ab+b^2))$

$= a^{3} b (a^{3} + 2 a^{2} + a^{2} b + 3 a b + b^{2}) \leftarrow$ $=a^3b(a^3+2a^2+a^2b+3ab+b^2)" "larr$ distribute the $a^{3} b$ $a^3b$

$= a^{6} b + 2 a^{5} b + a^{5} b^{2} + 3 a^{4} b^{2} + a^{3} b^{3}$ $=a^6b +2a^5b+a^5b^2+3a^4b^2+a^3b^3$