Question

Question #a92bd

Answer 1

`x^12-y^12`

Explanation:

`(x-y)(x+y)(x^2+y^2)(x^2+xy+y^2)(x^2-xy+y^2)(x^4-x^2y^2+y^4)`

`(x^2+x y + y^2)=(x^3-y^3)/(x-y)`
`(x^2-x y + y^2)=(x^3+y^3)/(x+y)`
`(x^4-x^2y^2+y^4)=(x^6+y^6)/(x^2+y^2)`

joining all that

`(x-y)(x+y)(x^2+y^2)(x^2+xy+y^2)(x^2-xy+y^2)(x^4-x^2y^2+y^4)=`

`=(x-y)(x+y)(x^2+y^2)(x^3-y^3)/(x-y)(x^3+y^3)/(x+y)(x^6+y^6)/(x^2+y^2)=`

`=(x^3-y^3)(x^3+y^3)(x^6+y^6) = x^12-y^12`