Question #8e319

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Answer 1 · 2017-05-25T11:30:37

$10%$ was added to the length and width.

Let $x %$ is increased in both length and width.

Increased length is $l*(1+0.01x)= l+ 0.01lx$

Increased width is $w*(1+0.01x)= w+ 0.01wx$

$l*w=300 ; (l+ 0.01lx) * (w+ 0.01wx)=363$

$lw+0.01x(lw+lw)+0.0001lwx^2=363$ or

$300 + 2*300*0.01x + 300*0.0001x^2=363$ or

$0.03x^2+6x-63=0 or 3x^2+600x -6300 =0$ or

$x^2+200x-2100 =0$

$(x+210)(x-10)=0 :. x=-210 or x=10$

$x$ cannot be negative so $x=10%$

$10%$ was added to the length and width. [Ans]