How many iron atoms are present in a $16*g$ mass of $FeCl_3$ ?

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Answer 1 · 2017-03-25T06:58:03

We work out the molar quantity of iron in a $16*g$ mass of $"ferric chloride....."$ and get approx. $6xx10^22$ individual iron atoms.

$"Moles of"$ $FeCl_3$ $=$ $"Mass"/"Molar mass"$

$=(16*g)/(162.2*g*mol^-1)=0.099*mol$

And so there $0.099*mol$ of iron, and $3xx0.099*mol$ of chlorine. How does that help us?

Well the mole is simply a number; one mole of stuff SPECIFIES precisely $6.022xx10^23$ individual items of stuff.

And here our stuff was $FeCl_3$ , and in each mole of this stuff there $3*mol$ of chlorine atoms..........BUT one mole of iron.

$"And so number of iron atoms......"$

$=0.099*molxx6.022xx10^23*mol^-1=5.96xx10^22*"iron atoms."$

How many iron atoms are present in a 16*g16*g mass of FeCl_3FeCl_3?