What is the molar solubility of Cd(OH)2 given Ksp=5.3×10−15?

1 Answer
anor277
Mar 20, 2017

[Cd(OH)2]=1.10×10−5⋅mol⋅L−1

Explanation:

For the reaction:

Cd(OH)2(s)⇌Cd2++2HO−

We write Ksp=[Cd2+][HO−]2

And if we call the solubility of Cd(OH)2, S, then.........

Ksp=S×(2S)2=4S3

And so S=3√Ksp4=3√5.3×10−154=1.10×10−5⋅mol⋅L−1, with respect to Cd(OH)2..........

If the pH of the solution were buffered to HIGH or LOW pH how would the solubility evolve?

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