What is the mass of a single $^{20} N e$ $""^20Ne$ atom?

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Answer 1 · 2017-03-21T08:37:59

We divide the $molar mass$ $"molar mass"$ by $Avogadro's number.........$ $"Avogadro's number........."$

And thus $atomic mass$ $"atomic mass"$ $=$ $=$ $\frac{Molar mass}{Avogadro's number}$ $"Molar mass"/"Avogadro's number"$

$=(20*g*mol^-1)/N_A=(20*g*cancel(mol^-1))/(6.022xx10^23*cancel(mol^-1))$

$=3.32xx10^-23*g$ .................

Note the dimensional consistency of the quotient; i.e. we wanted an answer with units of mass, and we got one......

What is the mass of a single ""^20Ne20Ne""^20Ne atom?