Question #96a4f

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Question #96a4f

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Answer 1 · 2017-03-25T18:45:26

The empirical formula is ${CuS}_{2}$ $"CuS"_2$ .

Explanation:

An empirical formula is the simplest whole number molar ratio of the elements in a compound.

Your compound contains $0.768 mol Cu$ $"0.768 mol Cu"$ and $1.56 mol S$ $"1.56 mol S"$ .

I like to summarize the calculations in a table.

$Element m Moles m Ratio m l Integers$ $bb("Element"color(white)(m) "Moles"color(white)(m) "Ratio"color(white)(m)color(white)(l)"Integers")$
$m Cu m m m l l 0.768 X m 1 m m m m m l l 1$ $color(white)(m)"Cu" color(white)(mmmll)0.768 color(white)(Xm)1color(white)(mmmmmll)1$
$m S m m m m l 1.56 X m l l 2.03 m m m m l 2$ $color(white)(m)"S"color(white)(mmmml)1.56" color(white)(Xmll)2.03 color(white)(mmmml)2$

There is 1 mol of $Cu$ $"Cu"$ for 2 mol of $S$ $"S"$ .

The empirical formula is ${CuS}_{2}$ $"CuS"_2$ .

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Question #96a4f

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