Question #13f21

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Answer 1 · 2017-03-28T07:43:52

The length of the wire is $=0.2m$

We apply the equation

$f=1/(2L)sqrt(T/mu)$

Frequency is $=f Hz$

Length of wire is $=L m$

Tension is $=T N$

Lineal density is $mu kgm^-1$

Initial conditions

$256=1/(2*0.8)sqrt(T/mu)$

$sqrt(t/mu)=256*2*0.8$

New frequency is

$f_1=1024=1/(2L_1)*256*2*0.8$

$L_1=256/1024*2*0.8/2$

$L_1=0.2m$