Question #6a6ad

Question

1382 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-30T04:10:10

$0=-16t^2+150$

$=>16t^2=150$

$=>t^2=150/16$

$=>t=sqrt(150/16)=(5sqrt6)/4$

Alternative

$16t^2-150=0$

$=>(4t)^2-(5sqrt6)^2=0$

$=>(4t-5sqrt6)(4t+5sqrt6)=0$

So $4t-5sqrt6=0$

$=>t=(5sqrt6)/4s$

Negative root rejected as $t<0$ not possible.