Question #f2b43

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Question #f2b43

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Answer 1 · 2017-03-31T03:20:02

perimeter $= 11.9957 m$ $= 11.9957 m$
area $= 5.8165 m^{2}$ $=5.8165 m^2$

Explanation:

enter image source here

I have to assume that the triangle shown in the figure is a right triangle.

To find the perimeter of this shape, we need to add up all the outside edges (the solid green lines and arcs).

$Y = \sqrt{{4.5}^{2} - 3^{2}} = 3.3541 m$ $Y=sqrt(4.5^2-3^2)=3.3541m$

perimeter $= 3.3541 + 4.5 + (3 - 1 - 1 + 2 \cdot π \cdot r)$ $= 3.3541+4.5+(3-1-1+2*pi*r)$
where r is the radius of the semi-circles ( $r = \frac{1}{2} \cdot$ $r=1/2*$ diameter).

$\Rightarrow$ $=>$ perimeter $= 3.3541 + 4.5 + (3 - 1 - 1 + 2 \cdot π \cdot \frac{1}{2})$ $= 3.3541+4.5+(3-1-1+2*pi*1/2)$
$= 11.9957 m$ $=11.9957m$

Area of the shape = area of triangle + area of the two semi-circles
$\Rightarrow$ $=>$ Area $= (\frac{1}{2} \cdot Y \cdot 3) + (π \cdot r^{2})$ $= (1/2*Y*3) + (pi*r^2)$
$= (\frac{1}{2} \cdot 3.3541 \cdot 3) + (π \cdot {(\frac{1}{2})}^{2})$ $=(1/2*3.3541*3)+(pi*(1/2)^2)$
$= 5.8165 m^{2}$ $=5.8165m^2$

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Question #f2b43

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