Question #efb68

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Question #efb68

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Answer 1 · 2017-04-03T05:51:14

The amount of water that the tank can hold is $135, 000 l$ $135,000l$ .
The total surface area of the tank is $159 m^{2}$ $159m^2$ .

Explanation:

To determine how many litres of water the tank can hold, we first calculate the volume according to the standard formula:

$V = l \times w \times d$ $V=lxxwxxd$ where $V =$ $V=$ Volume, $l =$ $l=$ length, $w =$ $w=$ width, and $d =$ $d=$ depth.

$V = 6 \times 5 \times 4.5$ $V=6xx5xx4.5$

$V = 30 \times 4.5$ $V=30xx4.5$

$V = 135$ $V=135$

The volume of the tank is $135 m^{3}$ $135m^3$

Since $1 m^{3} = 1000 l$ $1m^3=1000l$ ,

$V = 135 \times 1000$ $V=135xx1000$

$V = 135, 000$ $V=135,000$

The amount of water that the tank can hold is $135, 000 l$ $135,000l$ .

The total surface area of a cuboid is calculated as the sum of the areas of the six faces (considering the tank to be closed on all sides) and has the formula:

$T S A = 2 (l \cdot w + w \cdot d + d \cdot l)$ $TSA=2(l*w+w*d+d*l)$

$T S A = 2 ([6 \cdot 5] + [5 \cdot 4.5] + [4.5 \cdot 6])$ $TSA=2([6*5]+[5*4.5]+[4.5*6])$

$T S A = 2 (30 + 22.5 + 27)$ $TSA=2(30+22.5+27)$

$T S A = 2 \times 79.5$ $TSA=2xx79.5$

$T S A = 159$ $TSA=159$

The total surface area of the tank is $159 m^{2}$ $159m^2$ .

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