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Answer 1 · 2017-04-05T23:00:12

Using Boyle's Law (from the combined Ideal Gas Law), we find that the new volume is 1.409 liters. (See explanation)

We can solve this by using a variation of the Ideal Gas Law (PV = nRT). This variation is the combined Ideal Gas Law:

$(P_1V_1)/T_1=(P_2V_2)/T_2$ , which allows us to compare the changes made to pressure, volume, and temperature.

Since temperature is constant, $T_1=T_2$ , so our new comparison would be: (Boyle's Law)

$P_1V_1=P_2V_2$

We need to find the new volume, $V_2$ , so we rearrange the equation:
$V_2=(P_1V_1)/P_2$

These are the values we have:
$V_1=3$ L
$P_1=101$ kPa
$P_2=215$ kPa

Plug in and solve:
$V_2=$ $((101 kPa)(3 L))/(215 kPa)=1.409 L$