Question

Question #ffcee

Answer 1

97.3%

Explanation:

Given the two masses, the density is irrelevant to the calculation.
M.W. `HNO_3` = 63 kg/kmol. M.W. `H_2O` = 18 kg/kmol
Mole percent = moles solute/(moles solvent + moles solute)
125 kg `HNO_3` = 1.98 kmol ; 1 kg `H_2O` = 0.0556 kmol

Mole percent = 1.98/(0.0556 + 1.98) = 0.973, or 97.3% `HNO_3`