Question

Question #5c77f

Answer 1

Option (5)

Explanation:

Formula to get the resolved part of a vector `vecV` along the direction making an angle `theta` with it is given by

`vecV_"resolved part"=vecVcostheta`

`vecA` makes an angle `theta=0^@` with the X-axis and it makes an angle `theta=90^@` with the Y-axis.

So its resolved part along X-axis

`vecA_x=vecAcos0^@`

And its resolved part along Y-axis

`vecA_y=vecAcos90^@`

Again `vecB` makes an angle `theta=(180^@-60^@)` with the X-axis and it makes an angle `theta=30^@` with the Y-axis.

So its resolved part along X-axis

`vecB_x=vecBcos(180^@-60^@)=-Bcos60^@`

And its resolved part along Y-axis

`vecB_y=vecBcos30^@`