How can we find DeltaH_"rxn"^@ for...? NaOH(s) + HCl(g) rarr NaCl(s) + H_2O(l)?

1 Answer
Apr 9, 2017

You normally would quote INDIVIDUAL DeltaH_f^@ for reactants and products.

I get DeltaH_"rxn"^@=-134.7*kJ*mol^-1.

Explanation:

But, we can find DeltaH_f^@ for the participating species on the [interwebz.....](https://en.wikipedia.org/wiki/Standard_enthalpy_of_formation) :

NaOH(s) + HCl(g) rarr NaCl(s) + H_2O(g)

And the various DeltaH_f^@ are taken from the given site.

NaOH(s), DeltaH_f^@=-426.0*kJ*mol^-1

NaCl(s), DeltaH_f^@=-411.2*kJ*mol^-1

HCl(g), DeltaH_f^@=-92.3*kJ*mol^-1

H_2O(g), DeltaH_f^@=-241.8*kJ*mol^-1

Now DeltaH_"rxn"^@=SigmaDeltaH_f^@"products"-SigmaDeltaH_f^@"reactants"

{(-241.8-411.2)-(-426.0-92.3)}*kJ*mol^-1=-134.7*kJ*mol^-1

If I were you, I would check on the DeltaH_f^@ values. All care taken, but no responsibility admitted.......