What is the formality of a 1.24*g1.24⋅g mass of "copper sulfate pentahydrate"copper sulfate pentahydrate in a 100*cm^3100⋅cm3 volume of solution?

1 Answer
anor277
Apr 7, 2017

"Formality"Formality == "Moles of solute"/"Volume of solution (L)"=0.05*mol*L^-1Moles of soluteVolume of solution (L)=0.05⋅mol⋅L−1.

Explanation:

"Concentration of sodium thiosulfate pentahydrate:"Concentration of sodium thiosulfate pentahydrate:

-=≡ ((1.24*g)/(248.18*g*mol^-1))/(100*cm^3xx10^-3*cm^-3*L)1.24⋅g248.18⋅g⋅mol−1100⋅cm3×10−3⋅cm−3⋅L

=0.0500*mol*L^-1=0.0500⋅mol⋅L−1 WITH RESPECT TO THE PENTAHYDRATE.

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