What mass of copper(II) chloride is required to prepare sodium chloride from a 3.65*g3.65⋅g mass of sodium metal?

1 Answer
anor277
Apr 8, 2017

Approx. 4*g4⋅g of "copper salt"copper salt are required.......

Explanation:

We have a molar quantity of (3.65*g)/(58.44*g*mol^-1)=0.0625*mol3.65⋅g58.44⋅g⋅mol−1=0.0625⋅mol with respect to NaClNaCl.

There is thus a molar quantity of 0.0625*mol0.0625⋅mol with respect to the chloride ion? Agreed.

And thus we need a 1/2*"equivalent"12⋅equivalent of "cupric chloride"cupric chloride, because by composition, each mole of CuCl_2CuCl2 supplies 2 moles of chloride ion...........

So thus we need 1/2xx0.0625*molxx134.45*g*mol^-112×0.0625⋅mol×134.45⋅g⋅mol−1

=4.20*g=4.20⋅g CuCl_2CuCl2 to supply the chloride ions.

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