Question #918e5

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Answer 1 · 2017-04-09T14:22:01

$x =-1 /2+-sqrt (1/4 - ln 2)$
or
$x = -0.500+-0.666i$

$ln 2 -x - ln 4 - x^2 =0$

$ln 2 - ln 4 = x^2 + x$

$ln 2 - ln 2^2 = x^2 + x$

$ln 2 - 2 ln 2 = x^2 + x$

$- ln 2 = x^2 + x$

$- ln 2 = (x + 1/2)^2 - (1/2)^2$

$1/4 - ln 2 = (x + 1/2)^2$

$+-sqrt (1/4 - ln 2) = x + 1/2$

$-1 /2+-sqrt (1/4 - ln 2) = x$

$-0.500+-sqrt (0.250 - 0.693) = x$

$-0.500+-sqrt ( - 0.443) = x$

$-0.500+-sqrt ( 0.443 * (-1)) = x$

$-0.500+-sqrt ( 0.443 * (i^2)) = x$ , where $i^2 = -1$

$-0.500+-sqrt ( 0.443 )i = x$

$-0.500+-0.666i = x$