How do you solve $2x^2 + 5x - 3 = 0$ ?

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Answer 1 · 2017-04-10T15:54:56

See the entire solution process below:

We can factor the left side of the equation as:

$(2x - 1)(x + 3) = 0$

We can now solve each term on the right side of the equation for $0$ :

Solution 1)

$2x - 1 = 0$

$2x - 1 + color(red)(1) = 0 + color(red)(1)$

$2x - 0 = 1$

$2x = 1$

$(2x)/color(red)(2) = 1/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 1/2$

$x = 1/2$

Solution 2)

$x + 3 = 0$

$x + 3 - color(red)(3) = 0 - color(red)(3)$

$x + 0 = -3$

$x = -3$

The solution is: $x = 1/2$ and $x = -3$

How do you solve 2x^2 + 5x - 3 = 02x^2 + 5x - 3 = 0?