Question #148c6

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Question #148c6

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Answer 1 · 2017-04-11T00:53:08

396.36 grams

Explanation:

You are asked to find the mass in grams but you are given moles .

We know that silver, $A g$ $Ag$ , has a molar mass of $107.87 \frac{g}{m o l}$ $107.87 g/(mol)$ . This means, for every $1 mole$ $1" mole"$ of $A g$ $Ag$ you have, there are $107.87 grams$ $107.87 "grams"$ of it. We will use this as our tool to convert $moles \to grams$ $"moles"->"grams"$ .

We will establish an approximation for the molar mass of $A g$ $Ag$

$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $107.87 \approx 108$ $107.87 approx 108$

$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$
Method
$(3.67 cancel"moles")/(1) * (108 g)/(1 cancel"mole")=396.36" grams of Ag"$

$Answer: 396.36" grams of Ag"$

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Question #148c6

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