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Question #51ed7

1 Answer

Apr 11, 2017

see below

Explanation:

$A = log 2$ $A=log2$ ,

$B = log 3$ $B=log3$

$log 36 = log (2 \cdot 2 \cdot 3 \cdot 3)$ $log 36 = log (2 * 2 * 3 * 3 )$

$= log 2 + log 2 + log 3 + log 3$ $= log 2 + log 2 + log 3 + log 3$

$= 2 A + 2 B$ $= 2A + 2B$

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