Question #b773e

1 Answer
Apr 11, 2017

DeltaH"of reaction"= "-121.2kJ/mol"

Explanation:

2CO + O_2 = 2CO_2

DeltaH"of reaction" = DeltaH_f^@ of "product(s)" - DeltaH_f^@ of "reactants"

The product in this reaction is CO

DeltaH_f^@ of CO is -253.7KJ/mol

The reactants in this reaction are O_2 and CO_2

But the DeltaH_f^@ of O_2 is not there

The DeltaH_f^@ of all elements is 0kJ/mol

So the DeltaH_f^@ of O_2 is
0kJ/mol

The combined DeltaH_f^@of products should be multiplied by their coefficients .

-253.7KJ/mol 2 + 0kJ/mol1 = -507.4kJ/mol

DeltaH_f^@ of products

CO_2 = -314.3kJ/mol

And remember also multiply by the coefficient

-314.3kJ/mol* 2 = -628.6

Plug the values in the equation

DeltaH"of reaction" = DeltaH_f^@ of "product(s)" - DeltaH_f^@ of "reactants"

"-628.6kJ/mol - (-507.4kJ/mol)"

DeltaH"of reaction"= "-121.2kJ/mol"