Question

What are the concentrations with respect to bromide, iodide, and hydronium ion for a solution prepared by mixing `150*mL` of `HI(aq)` at `0.1*mol*L^-1` concentration, and `50*mL` of `HBr(aq)` at `0.05*mol*L^-1` concentration?

Answer 1

We assume (reasonably) that the volumes are additive...........

Explanation:

And thus the total volume of solution is `(50+150)*mL`, i.e. `0.200*L.`

For each species we remember that `"concentration"="moles"/"volume"`, and thus `"number of moles"="volume"xx"concentration"`

`[I^-]=(0.150*Lxx0.1*mol*L^-1)/(0.200*L)=0.075*mol*L^-1`.

`[Br^-]=(0.50*Lxx0.05*mol*L^-1)/(0.200*L)=??*mol*L^-1`.

`[H_3O^+]=(0.150*Lxx0.1*mol*L^-1+0.50xx0.05*mol*L^-1)/(0.200*L)=?`.