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Question #48b84

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Apr 13, 2017

We use the relationship, $Concentration = \frac{Moles of solute}{Volume of solution.}$ $"Concentration"="Moles of solute"/"Volume of solution."$

Explanation:

And thus we solve for..........

$Volume of solution \times concentration = Moles of solute$ $"Volume of solution"xx"concentration"="Moles of solute"$

(we assume, here, REASONABLY, that the volume of the solvent will not change overmuch when the calcium chloride salt is dissolved in it).

So $Moles of solute = 1 \cdot L \times 0.10 \cdot m o l \cdot L^{- 1} = 0.10 \cdot m o l$ $"Moles of solute"=1*Lxx0.10*mol*L^-1=0.10*mol$ .

And this represents a mass of $0.10 \cdot m o l \times 110.98 \cdot g \cdot m o l^{- 1}$ $0.10*molxx110.98*g*mol^-1$

$= 11.10 \cdot g$ $=11.10*g$ .

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