Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Question #5a26c

1 Answer

Apr 19, 2017

$f^(-1)(x)=+-sqrt(2x+10)$

Explanation:

$y=1/2 x^2-5$

$"solve for x"$

$y+5=1/2x^2$

$2(y+5)=x^2$

$2y+10=x^2$

$x=+-sqrt(2y+10)$

$"substitute y=x"$

$y=+-sqrt(2x+10)$

$f^(-1)(x)=+-sqrt(2x+10)$

Related questions

See all questions in Quadratic Functions and Their Graphs

Impact of this question

1165 views around the world

You can reuse this answer
Creative Commons License