Given a mass of $8 \cdot g$ $8*g$ of oxygen gas, what is the molar quantity?

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Given a mass of $8 \cdot g$ $8*g$ of oxygen gas, what is the molar quantity?

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Answer 1 · 2017-09-09T05:35:16

Approx. $0.25 \cdot m o l$ $0.25*mol$ ...............with respect to dioxygen gas.....

Explanation:

You must simply know that oxygen, as are most of the elemental gases, certainly those that have any chemistry, is a BINUCLEAR gas, i.e. $O_{2}$ $O_2$ ....

And so we take $\frac{mass}{molar mass}$ $"mass"/"molar mass"$ to get an answer in moles....

$\frac{8 \cdot g}{32.0 \cdot g \cdot m o l^{- 1}} = \frac{1}{4} \cdot m o l$ $(8*g)/(32.0*g*mol^-1)=1/4*mol$

How many oxygen atoms in this mass?

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Given a mass of $8 \cdot g$ $8*g$ of oxygen gas, what is the molar quantity?

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Given a mass of 8⋅g8*g of oxygen gas, what is the molar quantity?

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Given a mass of $8 \cdot g$ $8*g$ of oxygen gas, what is the molar quantity?