Question #e4fa1

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Question #e4fa1

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Answer 1 · 2017-07-06T14:28:19

Hello, please recheck the question.. i don't understand the x2 one side..

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Try rephrasing the question, but the others, i understand what you mean..

Update it and tag me via comment to answer it..

Answer 2 · 2017-07-15T11:51:02

Option C: $432 m^{2}$ $" "432m^2$

Explanation:

Start by choosing a variable for the two equal sides of the triangle.

Let the side be $x$ $x$ .

The base is $12$ $12$ less than twice $x$ $x$ .

The length of the base is: $2 x - 12$ $2x-12$

But the base has a length of $48$ $48$ , write an equation and solve it.

$2 x - 12 = 48 \to 2 x = 60 \to x = 30$ $2x-12 = 48" "rarr 2x = 60" "rarr x=30$

Now that we have the sides of the triangle, we can find its area.
But in order to do so we need the height. Use Pythagoras's Theorem to find the height;

$h^{2} = 30^{2} - 24^{2} = 324$ $h^2 = 30^2-24^2 = 324$

$h = \sqrt{324} = 18$ $h = sqrt324 = 18$

$a r e a = \frac{b \times h}{2}$ $area = (bxxh)/2$

$a r e a = \frac{48 \times 18}{2}$ $area = (48 xx18)/2$

$a r e a = 432 m^{2} \leftarrow$ $area = 432 m^2" "larr$ option C

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